Two similar triangles have bases s and S. If the area of the triangle with base S is twice the area of the tiangle with base s, then in terms of s, S =
a) ((sqrt2)s)/2
b) ((sqrt3)s)/2
c) (sqrt2)s
d) (sqrt3)s
e) 2s
a) ((sqrt2)s)/2
b) ((sqrt3)s)/2
c) (sqrt2)s
d) (sqrt3)s
e) 2s
