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GMAT prep geometry/ratio

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by awilhelm » Tue Jan 20, 2009 2:52 pm
Two similar triangles have bases s and S. If the area of the triangle with base S is twice the area of the tiangle with base s, then in terms of s, S =

a) ((sqrt2)s)/2
b) ((sqrt3)s)/2
c) (sqrt2)s
d) (sqrt3)s
e) 2s
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Re: GMAT prep geometry/ratio

by piyush_nitt » Tue Jan 20, 2009 8:37 pm
awilhelm wrote:Two similar triangles have bases s and S. If the area of the triangle with base S is twice the area of the tiangle with base s, then in terms of s, S =

a) ((sqrt2)s)/2
b) ((sqrt3)s)/2
c) (sqrt2)s
d) (sqrt3)s
e) 2s
ratio of Area of similar triangles = ratio of square of similiar sides

therefore

A2 = 2* A1

A1/A2 = s^2/S^2

A1/2A1 = s^2/S^2

1/2 = s^2/S^2

1/sqrt(2) = s/S

S = sqrt(2)s

IMO D
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by awilhelm » Wed Jan 21, 2009 8:37 am
The answer is C, but you got it right. Thanks for the explanation.
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