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by gmat083 » Fri Sep 03, 2010 3:16 pm
ankur.agrawal wrote:If n is a positive integer, what is the remainder when 3^8n+3 + 2 is divided by 5?
answer is 3
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by rohit_gmat » Fri Sep 03, 2010 11:23 pm
sorry the question is not clear.
Is it 3^(8n + 3 +2) or something else?
What are the Answer choices? Whats the source?
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by shibal » Sat Sep 04, 2010 5:01 am
ankur.agrawal wrote:If n is a positive integer, what is the remainder when 3^8n+3 + 2 is divided by 5?
IMO: 3

patterns for 3 squared is: 3,9,7,1.....

so by plugging in # we can find the pattern. for n=1 we'll have 3^13. going back to pattern i just mentioned, u'll find out that the 13th pattern is 3.
plug in 2; it'll output 3^21. go back to pattern and u'll find out once again that the 21st pattern is also 3....

OA?
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by arora007 » Sat Sep 04, 2010 11:51 am
Guys have a look at this flash card...
https://www.beatthegmat.com/papgust-s-gm ... tml#259476

Unit's place that has digits - 2/3/7/8

Then, unit's digit repeats every 4th value. Divide the power (or index) by 4.

After dividing,
If remainder is 1, unit digit of number raised to the power 1.
If remainder is 2, unit digit of number raised to the power 2.
If remainder is 3, unit digit of number raised to the power 3.
If remainder is 0, unit digit of number raised to the power 4.

effectively, three is raised to three and then two is added,

so (27+2)/5 the remainder should be 4.....whatsay??
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