BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Integers

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Tue Apr 28, 2009 10:26 am
by highlydetermined » Thu Jul 16, 2009 11:00 am
Is there a quick way of figuring out how many integers there are between 250 and 300, inclusive, that can be evenly divided by NEITHER 3 NOR 5?

Listing all the numbers are time consuming and not advisable for the GMAT.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Quantitative Reasoning |
Master | Next Rank: 500 Posts
Posts: 322
Joined: Fri Mar 27, 2009 3:56 pm
Thanked: 24 times
GMAT Score:710

by mike22629 » Thu Jul 16, 2009 11:45 am
Number of total integers = 300 - 250 + 1 = 51

Total Divisible by 3 = (300 - 252)/3 = 16

Total Divisible by 5 = (300 - 250)/5 = 10

Total Divisible by both = 255, 270, 290
(first first one divisble by both and add 15 to each one)

16 + 10 - 3 = 23 ( are divisible by either)

51 - 23 = 28 (not divisible)

IMO 28

Looks long when you write it out, but only took me about 1 min to solve.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Tue Apr 28, 2009 10:26 am

by highlydetermined » Thu Jul 16, 2009 12:21 pm
Thanks for the short cut, but the book has an answer of 27. There are 11 integers divisible by 5 and 13 integers divisible by 3, for a total of 24.

51-24=27
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Thu Jul 16, 2009 4:46 pm
mike's method is Ok but his counting is wrong
total number of integers=51
total divisible by 3=(300-252)/3+1=17
total divisible by 5=(350-250)/5+1=11
divisible by both=(300-250)/15 (take the quotient)+1 i.e. 4 and the numbers are 255,270,285 and 300
17+11-4=24

so numbers not divisible=51-24=27
The powers of two are bloody impolite!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1