Integers

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Integers

by bburton11 » Thu Jun 18, 2009 8:46 am
If n is a postive interger, which of the following must be an even interger?

n+1
n+2
n^2+2
n^2+n
n^2+2n

answer is n^2+n

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by ghacker » Thu Jun 18, 2009 9:12 am
take any two consecutive integers , they differ by one hence one is odd and the other is even .If you multiply the two you always get an even number

if n is an integer then n and n+1 are consecutive integers
when you multiply n and n+1 you should get an even number

n*(n+1) = even ------------n^2+n is even