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thegmatbeater
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integers
Source: Beat The GMAT — Data Sufficiency |
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cubicle_bound_misfit
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IMO it is C.
stmt 1 does not talk about P
stmt 2 both can be negative or positive.
combining n> -1 and np>0 as n is integr it can not be 0 so n starts from 1 so does p.
regards,
stmt 1 does not talk about P
stmt 2 both can be negative or positive.
combining n> -1 and np>0 as n is integr it can not be 0 so n starts from 1 so does p.
regards,
Cubicle Bound Misfit
Answer would be C.
Explanation:
Option 1 doesn't give any conclusive explanation regarding the range of P.
Option 2 says np>0 so both of them are either positive or negative. So, alone cannot be sufficient to say p>0
Using both of them, np>0 so n is not equal to 0 and p is not equal to 0. and since n>-1, n can only be positive. since np>0, p should also be positive!
Explanation:
Option 1 doesn't give any conclusive explanation regarding the range of P.
Option 2 says np>0 so both of them are either positive or negative. So, alone cannot be sufficient to say p>0
Using both of them, np>0 so n is not equal to 0 and p is not equal to 0. and since n>-1, n can only be positive. since np>0, p should also be positive!
IMO E.
1) n+1>0
2) np>0
From 1) it means that n > -1 , so n can still be negative number such as -0.5 or it can also be a positive number such as 2.
If n = -0.5, then p must be negative in order to make np>0
If n = 2, then p must be positive in order to make np>0
Therefore, it's inconclusive that p is positiveor nagative.
1) n+1>0
2) np>0
From 1) it means that n > -1 , so n can still be negative number such as -0.5 or it can also be a positive number such as 2.
If n = -0.5, then p must be negative in order to make np>0
If n = 2, then p must be positive in order to make np>0
Therefore, it's inconclusive that p is positiveor nagative.
How can we consider value of n as -0.5, when it is clearly mentioned that n & p are integers?
The value can be either 1 or 2 or any other number more than -1. What do you think?
MSD
The value can be either 1 or 2 or any other number more than -1. What do you think?
MSD
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