F(0+0) = F(0)*F(0)Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?
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0
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F(0) = F(0)^2
F(0) = 1 or 0
It could be either
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harsh.champ
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My take on the question will be:-Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?
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1
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-1
-10
Lets say x=0 and y=1
Then,F(0+1)=F(0)F(1)
=>F(1) = F(0)F(1)
=>F(1)[F(0) - 1] = 0
Hence,either [spoiler]F(1) = 0 or F(0) = 1.[/spoiler]
Hence the option would be B.
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shashank.ism
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F(X+Y)=F(x)F(y) -putting x= 0 , y = 1, we get F(0+1) = F(0) F(1)--->( f(0)-1)f1 =0 --> [spoiler]f(0) Ans D[/spoiler]Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?
10
1
0
-1
-10
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shashank.ism wrote:F(X+Y)=F(x)F(y) -putting x= 0 , y = 1, we get F(0+1) = F(0) F(1)--->( f(0)-1)f1 =0 --> [spoiler]f(0) Ans D[/spoiler]Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?
10
1
0
-1
-10
Dude,
How can you conclude D as answer from ( f(0)-1)f1 =0
either f1 =0
or f(0) = 1
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Dunno ...but as a guess
Also :-
F(1+0) = F(1). F(0)
[spoiler]F(1) = F(1) => F(0) = 1
Hence My answer is B [/spoiler]
Also :-
F(1+0) = F(1). F(0)
[spoiler]F(1) = F(1) => F(0) = 1
Hence My answer is B [/spoiler]
