2y>3z same as 6y>9z
A:
===
3y>2z ===> 6y > 4z
B:
===
y<2z ====> 6y <12z
Both together 4z < 6y <12z
Therefore, 6y may or may not be greater than 9z. Answer is E!
Inequalities
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
namitrajiv
- Junior | Next Rank: 30 Posts
- Posts: 25
- Joined: Thu Oct 02, 2008 2:11 pm
- Thanked: 3 times
should be E
We need to find if y>1.5 z
first statement says y>0.66 Z , clearly insufficient because if y >0.66 z it can or cannot be greater than 1.5 z
2nd statement says y<2z, again insufficient because if y <2z it can or cannot be greater than 1.5 z
combined 0.66z<y<2z
again y can be greater than or less than 1.5 z , possible values of y are
1.2 z(<1.5z), 1.7z(>1.5z)
We need to find if y>1.5 z
first statement says y>0.66 Z , clearly insufficient because if y >0.66 z it can or cannot be greater than 1.5 z
2nd statement says y<2z, again insufficient because if y <2z it can or cannot be greater than 1.5 z
combined 0.66z<y<2z
again y can be greater than or less than 1.5 z , possible values of y are
1.2 z(<1.5z), 1.7z(>1.5z)
-
gmat009
- Master | Next Rank: 500 Posts
- Posts: 458
- Joined: Sun Aug 31, 2008 10:44 am
- Thanked: 3 times
- Followed by:1 members
Yes you are right....namitrajiv wrote:should be E
We need to find if y>1.5 z
first statement says y>0.66 Z , clearly insufficient because if y >0.66 z it can or cannot be greater than 1.5 z
2nd statement says y<2z, again insufficient because if y <2z it can or cannot be greater than 1.5 z
combined 0.66z<y<2z
again y can be greater than or less than 1.5 z , possible values of y are
1.2 z(<1.5z), 1.7z(>1.5z)
By mistake I understood in a wrong way.
