(1/5)^m (1/4)^18 = 1/[2(10)^35]Frances87 wrote:Sorry if this question has already been posted before, but it came up on a practise test I took, and I am stuck as to how to solve it:
If (1/5)m(1/4)18 = 1/2(10)35, m?
a. 18
b. 17
c. 21
d. 35
e. 3
The answer is D
=> 5^(-m)*2^(-36) = 2^(-1)*(10)^(-35)
=> 5^(-m)*2^(-36) = 2^(-1)*5^(-35)*2^(-35)
=> 5^(-m)*2^(-36) = 5^(-35)*2^(-36)
Thus -m = -35; or m=35
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please write a raised to power b as -> a^b
1/a^x = (1/a)^x = a^(-x)
