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fraction and exponent question

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by Frances87 » Mon Feb 21, 2011 12:27 pm
Sorry if this question has already been posted before, but it came up on a practise test I took, and I am stuck as to how to solve it:

If (1/5)m(1/4)18 = 1/2(10)35, m?

a. 18
b. 17
c. 21
d. 35
e. 3

The answer is D
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Source: — Problem Solving |

by stormier » Mon Feb 21, 2011 1:05 pm
Frances87 wrote:Sorry if this question has already been posted before, but it came up on a practise test I took, and I am stuck as to how to solve it:

If (1/5)m(1/4)18 = 1/2(10)35, m?

a. 18
b. 17
c. 21
d. 35
e. 3

The answer is D
(1/5)^m (1/4)^18 = 1/[2(10)^35]

=> 5^(-m)*2^(-36) = 2^(-1)*(10)^(-35)
=> 5^(-m)*2^(-36) = 2^(-1)*5^(-35)*2^(-35)
=> 5^(-m)*2^(-36) = 5^(-35)*2^(-36)

Thus -m = -35; or m=35
__________________________

please write a raised to power b as -> a^b

1/a^x = (1/a)^x = a^(-x)
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by garuhape » Mon Feb 21, 2011 3:22 pm
Stomier,

can you please explain the general rule behind switching 4^18 to 2^36

Thx
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by garuhape » Mon Feb 21, 2011 3:24 pm
garuhape wrote:Stomier,

can you please explain the general rule behind switching 4^18 to 2^36

Thx
I got it ;)

4*4 = 4^2 = 2*2*2*2 = 2^4
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by stormier » Mon Feb 21, 2011 3:34 pm
garuhape wrote:
garuhape wrote:Stomier,

can you please explain the general rule behind switching 4^18 to 2^36

Thx
I got it ;)

4*4 = 4^2 = 2*2*2*2 = 2^4

(a^b)^c = a^(bc)

4^18 = (2^2)^18 = 2^(18*2) = 2^36


However,

a^(b^c) is not equal to a^bc
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by Frances87 » Tue Feb 22, 2011 3:27 am
Thanks Stormier, great explanation!
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