Value of x should be between -1 and 5 (0,1,2,3,4) -1 < x < 5 (not restricted to integers)
Since its a MUST be true question, we need to find at least one value outside this range so that the condition need not be true.
A. |3 - x| < -3 --- Value inside Mod is always +ve, LHS cannot be < -3 (This Options seems to be wrongly phrased)
B. -1< |x| < 5 - Sub x=-4 which satisfies this condition but is not in our set defined - Eliminate
C. |x| - 2 > 2 --- x can be 10 - Eliminate
D. |2 + x| > 3 ---- x can be 10 - Eliminate
E. |x - 2| < 3 - Since mod is always +ve or 0
x can only take 0,1,2,3,4 (-1<x<5) and all values are within our set defined. Hence this must be true. E IMO
Also helpful to know whenever there is a mod along with <,> signs, such as
|x| > 3(or) some number, we have no essential restrictions for values x can take
whereas, |x| < 3, limits the possibilities of values x can take.
In this problem, C and D can be checked last only when other options do not get you to the answer. Could save a few seconds/minutes in the exam.
Last edited by shankar.ashwin on Thu Jan 05, 2012 12:37 am, edited 2 times in total.