Inequality !!

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Inequality !!

by adi_800 » Sun Oct 09, 2011 1:16 am
If ab − bc2 < 0, is a < 0?

(1) c > 0

(2) b < 0

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by parul9 » Sun Oct 09, 2011 1:22 am
If ab - bc2 < 0, is a < 0?

(1) c > 0

(2) b < 0

If the equation in the qsn is ab - bc ^2 < 0, then I think the answer is B.
What is the OA?

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by CaptainHaddock » Sun Oct 09, 2011 2:44 am
Why is it not B? What's the solution you have?

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by parul9 » Sun Oct 09, 2011 4:33 am
CaptainHaddock wrote:Why is it not B? What's the solution you have?
It is B. Made a typo before.

Approach:
Eqn can be rewritten as b(a-c^2)<0, so either b < 0 or a-c^2<0

(1) c>0
We can't derive to any conclusion from this.

(2) b<0
this means, a-c^2>0
or a>c^2

C^2 will always be greater than 0.
So, a > 0.

We can answer the qsn using statement 2 alone.

Hence the answer would be B.