If ab − bc2 < 0, is a < 0?
(1) c > 0
(2) b < 0
Inequality !!
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It is B. Made a typo before.CaptainHaddock wrote:Why is it not B? What's the solution you have?
Approach:
Eqn can be rewritten as b(a-c^2)<0, so either b < 0 or a-c^2<0
(1) c>0
We can't derive to any conclusion from this.
(2) b<0
this means, a-c^2>0
or a>c^2
C^2 will always be greater than 0.
So, a > 0.
We can answer the qsn using statement 2 alone.
Hence the answer would be B.