Both on their own is NOT SUFF as we don't have enough info:
Together:
Say Length = l, width = w and height = h
we're lloking for l x w x h = volume
but from (1): l x w = 15 and w x h = 24
from (2) l x h = 40
so now we have 3 unknowns with 3 equations, so you'll be able to work it out.
So IMO C.
21q17
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Source: Beat The GMAT — Data Sufficiency |
- codesnooker
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(A) should be the answer.
L x W = 24 = 8 x 3
W x H = 15 = 5 x 3
So when you factorize above both equation, you can figure out the value of W = 3.
Therefore H = 5 and L = 8.
Hence volume = 3 x 5 x 8
Hence (A) is alone sufficient.
L x W = 24 = 8 x 3
W x H = 15 = 5 x 3
So when you factorize above both equation, you can figure out the value of W = 3.
Therefore H = 5 and L = 8.
Hence volume = 3 x 5 x 8
Hence (A) is alone sufficient.
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stubbornp
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codesnooker wrote:(A) should be the answer.
L x W = 24 = 8 x 3
W x H = 15 = 5 x 3
So when you factorize above both equation, you can figure out the value of W = 3.
Therefore H = 5 and L = 8.
Hence volume = 3 x 5 x 8
Hence (A) is alone sufficient.
Codesnooker,Isn't there is one case L x W=24 = 24 x 1
W x H=15 x 1
here we can figure out W=1...what do you say?
- codesnooker
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Hmm. You are correct. My apologizes for the mistake.stubbornp wrote:codesnooker wrote:(A) should be the answer.
L x W = 24 = 8 x 3
W x H = 15 = 5 x 3
So when you factorize above both equation, you can figure out the value of W = 3.
Therefore H = 5 and L = 8.
Hence volume = 3 x 5 x 8
Hence (A) is alone sufficient.
Codesnooker,Isn't there is one case L x W=24 = 24 x 1
W x H=15 x 1
here we can figure out W=1...what do you say?
-
gmattakers
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