Both on their own is NOT SUFF as we don't have enough info:

Together:

Say Length = l, width = w and height = h

we're lloking for l x w x h = volume

but from (1): l x w = 15 and w x h = 24

from (2) l x h = 40

so now we have 3 unknowns with 3 equations, so you'll be able to work it out.

So IMO C.

(A) should be the answer.

L x W = 24 = 8 x 3
W x H = 15 = 5 x 3

So when you factorize above both equation, you can figure out the value of W = 3.

Therefore H = 5 and L = 8.

Hence volume = 3 x 5 x 8

Hence (A) is alone sufficient.

codesnooker wrote:(A) should be the answer.

L x W = 24 = 8 x 3
W x H = 15 = 5 x 3

So when you factorize above both equation, you can figure out the value of W = 3.

Therefore H = 5 and L = 8.

Hence volume = 3 x 5 x 8

Hence (A) is alone sufficient.

Codesnooker,Isn't there is one case L x W=24 = 24 x 1
W x H=15 x 1

here we can figure out W=1...what do you say?

stubbornp wrote:

codesnooker wrote:(A) should be the answer.

L x W = 24 = 8 x 3
W x H = 15 = 5 x 3

So when you factorize above both equation, you can figure out the value of W = 3.

Therefore H = 5 and L = 8.

Hence volume = 3 x 5 x 8

Hence (A) is alone sufficient.

Codesnooker,Isn't there is one case L x W=24 = 24 x 1
W x H=15 x 1

here we can figure out W=1...what do you say?

Hmm. You are correct. My apologizes for the mistake.

I think both 1 and 2 are needed