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Ilikemeat321
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Thu Jul 24, 2008 7:33 am
Question # 8
A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has. How much does A have?
(A) 20
(B) 48
(C) 32
(D) 36
(E) 40
Way I did this:
Let N be how much A has
B+C = 1/4 *n
N= n/4+ 18 ?
the offical answer is:
N= n/4+n/4+18
can someone explain to me where that extra n/4 comes from?
A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has. How much does A have?
(A) 20
(B) 48
(C) 32
(D) 36
(E) 40
Way I did this:
Let N be how much A has
B+C = 1/4 *n
N= n/4+ 18 ?
the offical answer is:
N= n/4+n/4+18
can someone explain to me where that extra n/4 comes from?












