=5^(x+2)/5^2<1
=5^x*5^2/5^2<1
=5^x<1 (Substituting, 5^0=1)
=5^x<5^0 (cancelling out 5 from both sides)
Therefore, x<1

Just wanted to know the basis for the correct answer.
cuz the equation in the question itself gives us the Statements 1 and 2

sabal wrote:I have my GMAT tomorrow ie 20th of Nov 08
This Question is from OG11 Diagnostic 33
Got a lil confused with this question

Q. Is 5^(x+2)/25<1?
1. 5^x <1
2. x<0

The OA is D
I solved the inequality in the question like this
=5^(x+2)<1*25
=5^(x+2)<25
=5^(x+2)<5^2 (cancelling out 5 from both sides)
=(x+2)<2
Therefore, x<0 (same as statement 2)

Another Way,
=5^(x+2)/5^2<1
=5^x*5^2/5^2<1
=5^x<1 (Substituting, 5^0=1)(same as Statement1!)
=5^x<5^0 (cancelling out 5 from both sides)
Therefore, x<0 (same as statement 2)

What is wrong in the way i solved it?
Is the way I solved this inequality wrong??
(The cancelling ou the base bit??)
have I got the DS logic wrong the last minute?
So if someone can just explain me this DS inequality, would be very happy!!!