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venn diagram?

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venn diagram?

by jopup » Sun Jun 15, 2008 7:18 pm
students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.

1. 120 students
2 40 like lima beans

is the answer 88?
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by netigen » Sun Jun 15, 2008 7:39 pm
Ans is E

insufficient to answer the Q
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by anshul265 » Sun Jun 15, 2008 7:40 pm
It will surely not be 88. The total number of student who dislike Lima beans is 80. Both from 1 and 2.

Is the answer E?
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Re: venn diagram?

by ildude02 » Mon Jun 16, 2008 12:00 pm
jopup wrote:students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.

1. 120 students
2 40 like lima beans

is the answer 88?
Can someone expain how to solve this problem? I figured that the answer is E, but I wasn't comfortable with my approach. If x is total students, =>, 2/3x = DB(dislike beans), 5/8(2/3x) = 5/12x (DB+DS) . We cna eliminate (2) for sure as INSUFF. Considering (1), 80 = DB, 50 = DB+ DS(dislike sprouts). I didn't get any number for likes, but I wanted to know if my approach is right , and if there is a better way to approach this problem and how you would solve it.
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by sanjaylakhani » Fri Jun 20, 2008 7:34 pm
Hi

The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.

Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)

so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer

As per above , D should be answer


can anyone explain what's wrong here
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by durgesh79 » Fri Jun 20, 2008 8:35 pm
sanjaylakhani wrote:Hi

The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.

Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)

so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer

As per above , D should be answer


can anyone explain what's wrong here
I think you are right, both statement 1 and 2 are giving same information.....

I made a venn diagram ... and i think the answer should be D...

OA Please
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by albertrahul » Sat Jun 21, 2008 6:41 am
This question could be solved by Venn diagram.

Statement 1 says: Total students = 120.

Hence: Students who dislike Lima Beans = 120 * 2/3 = 80
Out of these, students who dislike Sprouts = 80 * 5/8 = 50
So total students who like sprouts but dislike beans = 80-50 = 30

So statement 1 is sufficient

Statement 2 says: 40 like Lima beans.
Hence 40 = 1/3 of total students, so total students = 120.
We can follow similar logic as above.
This statement is sufficient as well.

Answer IMO = D.
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by rakesheval » Sat Jun 21, 2008 8:59 am
answer is d..make a venn diagram..that should be helpful..
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