The answer is Eern5231 wrote:32) Is (a^2) b + a (b^2) > 0 ?
(1) a <0
(2) a+b<0
Instructors plz help...Inqeuality DS 32
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ankur_swayam
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glorydefined
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sanjana
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IMO : E
Question :
is (a^2)b + a(b^2) > 0
==>is ab(a+b) > 0
for this to be true we have 2 cases :
1)ab>0 and (a+b) >0
2)ab<0 and (a+b) <0
Statement 1
Tells us a<0 but gives no information on b,hence insufficient
statement 2
Tells us (a+b) < 0 ,
This tells us nothig about a and b individually so we cant say if ab >0 or ab < 0,hence insufficient
Pick numbers to verify :
a=-1,b=-5 ==> -1-5 <0
a=-7,b=2 ==> =7+2 <0
Together again,
We know a<0 and we know a+b <0 but we dont know the sign of b and hence both statements togetjer are also insufficient.
Question :
is (a^2)b + a(b^2) > 0
==>is ab(a+b) > 0
for this to be true we have 2 cases :
1)ab>0 and (a+b) >0
2)ab<0 and (a+b) <0
Statement 1
Tells us a<0 but gives no information on b,hence insufficient
statement 2
Tells us (a+b) < 0 ,
This tells us nothig about a and b individually so we cant say if ab >0 or ab < 0,hence insufficient
Pick numbers to verify :
a=-1,b=-5 ==> -1-5 <0
a=-7,b=2 ==> =7+2 <0
Together again,
We know a<0 and we know a+b <0 but we dont know the sign of b and hence both statements togetjer are also insufficient.
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umaa
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IMO E.ern5231 wrote:Is (a^2) b + a (b^2) > 0 ?
(1) a <0
(2) a+b<0
Can we follow this approach -
(a^2)b>-a(b^2)
Hence, Is a>-b?
(1) does not make it suff
(2) a<-b looks suff
Hence B. Am I going wrong anywhere?
We can write (a^2) b + a (b^2) > 0 as ab(a+b) > 0.
a+b<0. it means,
a b
- -
- +
+ -
There are three possibilities.
If one is negative and the other is positive, the answer might be negative.
But if both are negative, the answer will be positive.
Since we're getting 2 kind of answers B is not sufficient.
Even if you take both the statements, you will get 2 answers. So, both the statements together are not sufficient.
What we think, we become
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crackgmat007
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In the rephrase. Since you dont know whether a or be is negative or positive, you need to consider different possibilities.ern5231 wrote:Thanks Sanjana and Umaa. Your explanations look good but can you point out the mistake with my approach?
IMO Rephrase is ab(a+b)>0
1. We dont the the sign of b
2. Given (a+b)<0. We dont know the sign of ab
1&2
From stmt 1, we know a<0. But we still dont know sign of b. Hence E.
