if n is a positive integer, is the value of b-a at least twice the value of 3^n-2^n?
1) a=2^n+1 and b=3^n+1
2) n=3
1) a=2^n+1 and b=3^n+1
2) n=3
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b-a = 3^(n+1) - 2^(n+1) = (3*(3^n))-(2*(2^n)) = (3^n) + (2*(3^n))-(2*(2^n)) > (2*(3^n))-(2*(2^n))1) a=2^n+1 and b=3^n+1
Is b-a > 3^3-2^3 = 192) n=3
romitvsingh wrote:if n is a positive integer, is the value of b-a at least twice the value of 3^n-2^n?
1) a=2^n+1 and b=3^n+1
2) n=3
Statement 1: a=2^n+1 and b=3^n+1romitvsingh wrote:if n is a positive integer, is the value of b-a at least twice the value of 3^n-2^n?
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