- piyush2694
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OA: Epiyush2694 wrote:Is x > y?
(1) x^2 < y
(2) x^(1/2) >y
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Redeem$$x\,\,\mathop > \limits^? \,\,y$$piyush2694 wrote:Is x > y?
(1) x^2 < y
(2) x^(1/2) >y
It´s not. Your mistake is the implication show in red.zzqtd wrote:Statement 1:
if x is 2, y=5, then 4<5, here 2<5, that is x<y
if x is 0.5, y=0.3, then 0.25<0.3, here 0.5>0.3, that is x>y
So we cant conclude that if x>y of x<y
Statement 2:
Here x>=0, if square both sides of the inequality,
we have x>y^2, then x>y
Thus, statement 2 only is sufficient.
Please let me know if this is correct