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In triangle ABC

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by ska7945 » Sun Sep 07, 2008 11:56 pm
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangular region RCS ?
(1) The area of triangular region ABX is 32.
(2) The length of one of the altitudes of triangle ABC is 8.
let's beat GMAT.
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Source: — Data Sufficiency |

Re: In triangle ABC

by sudhir3127 » Mon Sep 08, 2008 8:53 am
ska7945 wrote:In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangular region RCS ?
(1) The area of triangular region ABX is 32.
(2) The length of one of the altitudes of triangle ABC is 8.
i go with A. and area of RCS is 4.

do let me know if its right so that i can post my solution.
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by shahdevang87 » Mon Sep 08, 2008 9:05 am
What's the OA? I will also go with A.
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by ramlakhavan » Mon Sep 08, 2008 9:26 am
IMO A, by Using similar triangles
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Explain your solution

by gmat_nov_2008 » Mon Sep 08, 2008 1:31 pm
Hi ramlakhavan,
How did you use similar triangles to solve this?

Thanks.
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by ska7945 » Mon Sep 08, 2008 5:03 pm
oa is a
and it doesnt state whether the triangle is right triangle.
let's beat GMAT.
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by sumithshah » Mon Sep 08, 2008 8:00 pm
can someone explain how?
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easy one

by Aspirant008 » Mon Sep 08, 2008 10:05 pm
similar triangles
abc is similar to xyz


the 2 mid point ones are simiollar
yea
but abx ?


axb is 32 so trapezium axyb is 64



and then.. u can find triangle is rcs
A is suff

Altitude with help , so b is insuff
a is ans

Regards,
Arshad
https://aim-mba.blocked
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by abcdefg » Wed Jul 15, 2009 3:16 pm
don't understand the suggested solution here. can someone help please. thanks.
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by abcdefg » Wed Jul 15, 2009 9:02 pm
I've attached a picture of the solution. What I don't get is what they mean by the triangles are similar since their corresponding interior angles have the same measure. How do we know that? Thanks.
Attachments
triangle.JPG
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Tough one

by rajshree.misra » Wed Jul 15, 2009 10:02 pm
Hey!

I came across this question in the MGMAT:

If Pool Y currently contains more water than Pool X, and if Pool X is currently filled to 2/7 of its capacity, what percent of the water currently in Pool Y needs to be transferred to Pool X if Pool X and Pool Y are to have equal volumes of water?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

(2) Pool X has a capacity of 14,000 gallons.

Any suggestions on the answer. Have a go at it. Will post the answer after I receive a few responses.

Thanks!
R
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by getso » Thu Jul 16, 2009 6:04 am
Hello .

I got we could solve by A. But Could you please provide me the explaination on how to deduce the area of Triangle RCS.

Thanks,
Shobha
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by abcdefg » Thu Jul 16, 2009 8:33 am
I'm posting the 2nd part of the solution. Now I understand why the triangles are similar but is there any quick way to do this problem? It took me a long long time to figure this problem out.

Almost impossible to solve given the time limits on the exam.
Attachments
triangle 2.JPG
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by hberens » Tue Jul 21, 2009 10:48 pm
It says in the provided solution that "BF, YG, and SH are perpendicular to AC". How can you assume that this is true? What if you didn't draw your triangle the way that they did? You can't assume that dropping a line from any corner of a triangle will result in a 90 degree angle.
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by glorydefined » Tue Aug 25, 2009 12:00 pm
Hey Rajshree,

Is the answer 'A' for your question?

Thanks,
Selva
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