The two teacher can occupy the beginning and end position in two ways. And for each of these two ways, the 3 students can occupy the middle 3 positions in 3*2*1 = 6 ways.sud21 wrote:2 teacher and 3 children queue up. There must be one teacher at the beginning and one teacher at the back. 3 children are in the middle. How many ways are possible?
Hence, a total of 2*6 = 12 arrangements are possible.
