If y ≠0, is a^x > y?
1) a = -y = |x|
2) a < 1
Statement 1: a = -y = |x|
Substituting a=|x| and y=-|x| into a^x > y, the question stem can be rephrased as follows:
Is |x|^x > -|x|?
Since y=-|x| and y≠0, x≠0 and |x| > 0.
Thus, the rephrased question stem implies the following:
Is (positive)^(nonzero power) > negative?
Since the left side must always be POSITIVE, while the right side must always be NEGATIVE, the answer to the question stem is YES.
Statement 2: a < 1
If a=0, x=1, and y=1, then a^x < y.
If a=0, x=1 and y=-1, then a^x > y.
INSUFFICIENT.
The correct answer is
A.
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