In the xy-coordinate plane, if the point (0,2) lies on the g

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

In the xy-coordinate plane, if the point (0,2) lies on the g

by BTGmoderatorDC » Mon Feb 11, 2019 4:57 pm

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In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

Source: Official Guide

Source: Beat The GMAT — Problem Solving | Mon Feb 11, 2019 4:57 pm

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members; Location: Vancouver, BC; Thanked: 5254 times; GMAT Score:770

by Brent@GMATPrepNow » Tue Feb 12, 2019 7:15 am

BTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

Source: Official Guide

KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1

So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2

Answer: A

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8132; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Wed Feb 13, 2019 6:32 pm

BTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

Source: Official Guide

We can substitute 0 for x and 2 for y and solve for k:

2(0) + k(2) = 4

2k = 4

k = 2

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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