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In the xy-coordinate plane, if the point (0,2) lies on the g

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by BTGmoderatorDC » Mon Feb 11, 2019 4:57 pm

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In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

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by Brent@GMATPrepNow » Tue Feb 12, 2019 7:15 am
BTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

Source: Official Guide
KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1

So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2

Answer: A

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Brent
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by Scott@TargetTestPrep » Wed Feb 13, 2019 6:32 pm
BTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. -1

E. -2

OA A

Source: Official Guide
We can substitute 0 for x and 2 for y and solve for k:

2(0) + k(2) = 4

2k = 4

k = 2

Answer: A

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