[GMAT math practice question]
In the x-y plane, what is the slope of the line segment joining the y-intercept and the positive x-intercept of the curve $$y=x^2-5x-6?$$
A. 1
B. 2
C. 3
D. 4
E. 5
In the x-y plane, what is the slope of the line segment join
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- Max@Math Revolution
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=>
First, we find the x-intercepts of the curve. These occur when y = 0. Now,
y=x^2-5x-6
=> y = (x+1)(x-6).
Thus, the x-intercepts are the points (-1,0) and (6,0), and the positive x-intercept is (6,0).
As the y-intercept occurs when x = 0, it is the point (0,-6).
Thus, the required slope is (6 - 0) / ( 0 - (-6) ) = 1.
Therefore, the answer is A.
Answer: A
First, we find the x-intercepts of the curve. These occur when y = 0. Now,
y=x^2-5x-6
=> y = (x+1)(x-6).
Thus, the x-intercepts are the points (-1,0) and (6,0), and the positive x-intercept is (6,0).
As the y-intercept occurs when x = 0, it is the point (0,-6).
Thus, the required slope is (6 - 0) / ( 0 - (-6) ) = 1.
Therefore, the answer is A.
Answer: A
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[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
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