A right cylinder soda can have a height of 8 and a radius of 3 as pictured above. What is the total surface area of the

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VJesus12: Legendary Member; Posts: 2276; Joined: Sat Oct 14, 2017 6:10 am; Followed by:3 members

A right cylinder soda can have a height of 8 and a radius of 3 as pictured above. What is the total surface area of the

by VJesus12 » Tue Aug 18, 2020 8:21 am

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A right cylinder soda can have a height of 8 and a radius of 3 as pictured above. What is the total surface area of the cylinder?

A. \(57\pi\)

B. \(60\pi\)

C. \(63\pi\)

D. \(66\pi\)

E. \(69\pi\)

Answer: D

Source: Veritas Prep

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Source: Beat The GMAT — Problem Solving | Tue Aug 18, 2020 8:21 am

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8086; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

Re: A right cylinder soda can have a height of 8 and a radius of 3 as pictured above. What is the total surface area of

by Scott@TargetTestPrep » Sat Aug 22, 2020 8:51 am

VJesus12 wrote: ↑
Tue Aug 18, 2020 8:21 am
Soda_Can.png

A right cylinder soda can have a height of 8 and a radius of 3 as pictured above. What is the total surface area of the cylinder?

A. \(57\pi\)

B. \(60\pi\)

C. \(63\pi\)

D. \(66\pi\)

E. \(69\pi\)

Answer: D

Solution:

Recall that the surface area of a cylinder of height h and base radius r is:

SA = 2πr^2 + 2πrh

Here, h = 8 and r = 3; therefore, the surface area of the cylinder is:

SA = 2π(3)^2 + 2π(3)(8)

SA = 18π + 48π

SA = 66π

Answer: D

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