In the given figure, if AS = 10 cm, SN = 5 cm and TN = 8 cm,
This topic has expert replies
-
- Moderator
- Posts: 7187
- Joined: Thu Sep 07, 2017 4:43 pm
- Followed by:23 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
-
- Legendary Member
- Posts: 2214
- Joined: Fri Mar 02, 2018 2:22 pm
- Followed by:5 members
Given that ;
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
$$5<AN<15$$
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\min imum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \max imum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
$$5<AN<15$$
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\min imum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \max imum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$
-
- Legendary Member
- Posts: 2214
- Joined: Fri Mar 02, 2018 2:22 pm
- Followed by:5 members
Given that ;
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
$$5<AN<15$$
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\min imum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \max imum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
$$5<AN<15$$
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\min imum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \max imum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$
-
- Legendary Member
- Posts: 2214
- Joined: Fri Mar 02, 2018 2:22 pm
- Followed by:5 members
Given that ;
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
5<AN<15
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\minimum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \maximum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$
AS = 10cm
SN = 5cm
TN = 8cm
In the triangle ABC with the sides abc : the sum of the length of any two sides of the triangle is greater than the length of the third considering ANS $$5+AN=10$$
$$AN<15$$
$$AN>5$$
5<AN<15
$$Hence,\ \ AN=6,7,\ ...............,\ 14$$
Minimum value of AN=6 Maximum value =14
Using the minimum and maximum value of AN in triangle ATN
$$AT>TN-AN\left(\minimum\ value\ of\ AT\right)$$
$$AT>8-6\left(where\ 6\ =\min\ no\ of\ AN\right)$$
$$AT>2$$
$$AT>2\left(\min\ value\ of\ AT\right)$$
$$AT<AN+TN\left(Maximum\ value\ of\ AT\right)$$
$$AT<14+8\left(where\ 8\ is\ the\ \maximum\ value\ of\ AN\right)$$
$$AT<22$$
$$Maximum\ value\ of\ AT\ is\ 21$$
$$Positive\ difference\ =21-3=18$$
$$answer\ is\ Option\ B$$