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Register now and save up to $200 Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Most awarded test prep in the world Now free for 30 days Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • Free Trial & Practice Exam BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code ## In the figure shown, the triangle This topic has 2 expert replies and 0 member replies boomgoesthegmat Senior | Next Rank: 100 Posts Joined 25 Apr 2016 Posted: 93 messages Upvotes: 1 #### In the figure shown, the triangle Wed May 04, 2016 4:47 am In the figure shown, the triangle is inscribed in the semicircle. If the length of line segment AB is 8 and the length of line segment BC is 6, what is the length of arc ABC? A) 15pi B) 12pi C) 10pi D) 7pi E) 5pi OA: E ### GMAT/MBA Expert DavidG@VeritasPrep Legendary Member Joined 14 Jan 2015 Posted: 2617 messages Followed by: 118 members Upvotes: 1153 GMAT Score: 770 Wed May 04, 2016 5:11 am See here for another good question that tests this principle: http://www.beatthegmat.com/inscribed-triangle-semicircle-t74152.html _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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### GMAT/MBA Expert

DavidG@VeritasPrep Legendary Member
Joined
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Posted:
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Wed May 04, 2016 5:06 am
boomgoesthegmat wrote:

In the figure shown, the triangle is inscribed in the semicircle. If the length of line segment AB is 8 and the length of line segment BC is 6, what is the length of arc ABC?

A) 15pi
B) 12pi
C) 10pi
D) 7pi
E) 5pi

OA: E
An inscribed angle opposite a circle's diameter is 90 degrees, so we know that angle ABC is a right angle. Moreover, we can see that triangle ABC is a 3:4:5 triangle, which means that if segment BC = 6 and AB = 8, then segment AC = 10. If the diameter is 10, the circumference of the full circle is 10pi. Here, arc ABC constitutes half the circle, or 5pi.

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