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In June 1989, what was the ratio of the number of sales tran

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In June 1989, what was the ratio of the number of sales transactions made by Salesperson X to the number of sales transactions made by Salesperson Y ?

(1) In June 1989, Salesperson X made 50 percent more sales transactions than Salesperson Y did in May 1989.
(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in May 1989.

OA C

Source: Official Guide
Source: — Data Sufficiency |

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by Jay@ManhattanReview » Thu Feb 28, 2019 10:05 pm

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BTGmoderatorDC wrote:In June 1989, what was the ratio of the number of sales transactions made by Salesperson X to the number of sales transactions made by Salesperson Y ?

(1) In June 1989, Salesperson X made 50 percent more sales transactions than Salesperson Y did in May 1989.
(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in May 1989.

OA C

Source: Official Guide
Say, in June 1989,

the number of sales transactions made by Salesperson X = x and
the number of sales transactions made by Salesperson Y = y.

We have to get the value of x /y.

Let's take each statement one by one.

(1) In June 1989, Salesperson X made 50 percent more sales transactions than Salesperson Y did in May 1989.

Since the comparison is made between sales figures of June and May, we can't get the value of x/y. Insufficient.

(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in May 1989.

No information about Salesperson X. Insufficient.

(1) and (2) together

From (2), we know that y = 125% of the numbers of sales transactions made by Salesperson Y in May.

Say Salesperson Y made p numbers of sales transactions than in May 1989.

Thus, y = 125% of y = 1.25p

From (1), we know that x = 150% of the numbers of sales transactions made by Salesperson Y in May.

Thus, x = 150% of x = 1.5p

Thus, x/y = (1.5p) / (1.25p) = 6/5. Sufficient.

The correct answer: C

Hope this helps!

-Jay
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