If 3 apples and 4 bananas costs $1.37, and $5 apples and 7 bananas costs $2.36, what is the total cost of 1 apple and 1

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$$Let\ price\ of\ 1\ apple\ =\ a\ and\ 1\ banana\ =\ b$$
$$3a+4b\ =$1.37.....eqn1$$
$$5a+7b\ =$2.36.....eqn2$$
$$from\ equation\ 1;\ b=\frac{1.37-39}{4}$$
$$from\ equation\ 2;\ \frac{5a}{1}+\frac{7}{1}\left(\frac{1.37-39}{4}\right)=2.36$$
$$\frac{5a}{1}+\frac{9.59-21a}{4}=2.36$$
$$\frac{20a+9.59-21a}{4}=2.36$$
$$20a-21a+9.59=9.44$$
$$-a=9.44-9.59$$
$$a=0.15$$
$$b=\frac{1.37-3\left(0.15\right)}{4}=\frac{1.37-0.45}{4}$$
$$b=\frac{0.92}{4}=0.23$$
$$1a+1s=0.15+0.23=$0.38$$
$$Answer\ =\ A$$

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AAPL wrote:
Mon Feb 01, 2021 4:41 am
Magoosh

If 3 apples and 4 bananas costs $1.37, and 5 apples and 7 bananas costs $2.36, what is the total cost of 1 apple and 1 banana?

A. $0.38
B. $0.39
C. $0.40
D. $0.41
E. $0.42

OA A
Solution:

Let a = the cost of 1 apple and b = the cost of 1 banana. We can create the equations:

3a + 4b = 1.37

And

5a + 7b = 2.36

Multiplying the first equation by 2, we have:

6a + 8b = 2.74

Subtracting the second equation from the above, we have:

a + b = 0.38

Answer: A

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