ardz24 wrote:The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
We can PLUG IN THE ANSWERS, which represent the number of rooms at G.
When the correct answer is plugged in, the number of rooms at G will be 10 less than twice the number of rooms at H.
D: G = 240
Since the total number of rooms at G and H = 425, H = 425-240 = 185.
10 less than twice H = (2*185) - 10 =
360.
Here, G is LESS than the value in blue, implying that the value of G must be BIGGER.
The correct answer is
E.
E: G = 280
Since the total number of rooms at G and H = 425, H = 425-280 = 145.
10 less than twice H = (2*145) - 10 =
280.
Success!
G is equal to the value in blue.
Algebra:
Since G is equal to 10 less than twice H, we get:
G = 2H - 10
Since the total number of rooms at G and H is 425, we get:
G + H = 425
H = 425 - G
Substituting H = 425-G into G = 2H - 10, we get:
G = 2(425-G) - 10
G = 850 - 2G - 10
3G = 840
G = 280.
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