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If [x, y, z]=(z+x)/(2z-y), then what is [3, -1, 2]?

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If [x, y, z]=(z+x)/(2z-y), then what is [3, -1, 2]?

by Max@Math Revolution » Sun Sep 22, 2019 11:44 pm

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[GMAT math practice question]

If [x, y, z]=(z+x)/(2z-y), then what is [3, -1, 2]?

A. -3
B. -1
C. 1
D. 3
E. 5
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by Max@Math Revolution » Tue Sep 24, 2019 11:57 pm
=>


We have [3, -1, 2] = (2+3)/(2*2-(-1)) = 5/5 = 1 by substituting in x = 3, y = -1 and z = 2.

Therefore, C is the answer.
Answer: C
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