If \(y= 4 + (x - 3)^2,\) then \(y\) is lowest when \(x =\)
A. 14
B. 13
C. 0
D. 3
E. 4
The OA is the option _D_
Source: Official Guide
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If y= 4 + (x - 3)^2, then y is lowest when
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Brent@GMATPrepNow
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KEY CONCEPT: In order to minimize the value of y, we must minimize the value of (x -3)²M7MBA wrote:If \(y= 4 + (x - 3)^2,\) then \(y\) is lowest when \(x =\)
A. 14
B. 13
C. 0
D. 3
E. 4
We know that (some number)² ≥ 0
So, the SMALLEST possible value of (some number)² is 0
Likewise, the SMALLEST possible value of (x -3)² is 0
(x -3)² = 0 when x = 3
Answer: D
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Brent
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Scott@TargetTestPrep
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SInce x - 3 is squared, we know that the smallest possible value of (x - 3)^2 is 0. Thus, when x = 3, the value of y will be the lowest.M7MBA wrote:If \(y= 4 + (x - 3)^2,\) then \(y\) is lowest when \(x =\)
A. 14
B. 13
C. 0
D. 3
E. 4
The OA is the option _D_
Source: Official Guide
Answer: D
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