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If (x+y)/z < 0, is x <0? (1) x<y (2)z<0

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by ronnie1985 » Thu Jan 05, 2012 1:11 am
S1. Insufficient as nothing is said of z and y
S2. x+y>0 is the implication, sign of x cannot be ascertained.
S1 and S2 combined also, sign of x cannot be ascertained. Hence (E) is answer.
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by ArunangsuSahu » Thu Jan 05, 2012 9:01 am
One Common mistake to avoid don't multiply z to 0 without knowing the nature of 'z'

Statement 1:
x < y

a) x can be +ive,0 or -ive
b) z is unknown
z can be less than 0. In that case (x+y) < 0. or x<-y.This satisfies as x<y and x<-y both takes x to negative direction.
z can be greater than 0. In that case (x+y) < 0 or x<-y.Doesn't satisfy the Given data is Statement1 .

So INSUFFICIENT

Statement 2:
z < 0.

In that case (x+y) < 0. or x<-y.
y is unknown
x= 2, y= -3..x>0
x=-3, y=-2..x<0

INSUFFICIENT

Combining (1) and (2)
we get the intersection
This satisfies as x<y and x<-y both takes x to negative direction.
a)x<y
b)x<-y
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by singalong » Fri Jan 13, 2012 7:11 pm
ArunangsuSahu wrote:One Common mistake to avoid don't multiply z to 0 without knowing the nature of 'z'

Statement 1:
x < y

b) z is unknown
z can be less than 0. In that case (x+y) < 0. or x<-y.This satisfies as x<y and x<-y both takes x to negative direction.
z can be greater than 0. In that case (x+y) < 0 or x<-y.Doesn't satisfy the Given data is Statement1 .
If z is greater than zero, how is (x+y)_< 0 ? shouldn't it be (x+y) > 0?
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by [email protected] » Thu Jan 19, 2012 11:11 pm
The correct answer is E if the sign given is less than 0

The correct answer is C if the sign given is greater than 0

Yes, the inequality was a good one...
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