Problem Solving

LUANDATO wrote:If x#y = yx^y for all values x and y, then 2#(0(-2#2)=

A. -64
B. 0
C. 32
D. 64
E. 128

The OA is B.

I don't have it clear. Can any expert explain this PS question please? Thanks.

We have to get the value of 2#(0(-2#2).

Let's first find out the value of (-2#2).

Comparing (-2#2) with x#y = yx^y, we see that here x = -2 and y = 2.

Thus, (-2#2) = 2.(-2)^2 = 2.4 = 8.

Thus, 2#(0(-2#2) = 2#(0(8)) = 2#0 = 0.2^0 = 0.1 = 0

The correct answer: B

Hope this helps!

-Jay

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BTGmoderatorLU wrote: ↑

Thu Oct 26, 2017 6:17 am

If x#y = yx^y for all values x and y, then 2#(0(-2#2)=

A. -64
B. 0
C. 32
D. 64
E. 128

The OA is B.

I don't have it clear. Can any expert explain this PS question please? Thanks.

First, we have; (-2#2) = 2(-2)^2 = 2(4) = 8

Next, we have: 0(8) = 0

Lastly, we have 2#0 = 0(2)^0 = 0

Answer: B