M7MBA wrote:If x > y, is x > 6 ?
(1) (x - 7)(y - 7) = 0
(2) x > 18 - 2y
Target question: Is x > 6 ?
Given: y < x
Statement 1: (x - 7)(y - 7) = 0
There are two possible cases that make this equation true. Either x = 7 OR y = 7
Let's examine each case:
Case a: x = 7. In this case,
the answer to the target question is YES, x IS greater than 6
Case b: y = 7. Since it is given that
y < x, we can now conclude that 7 < x.
The answer to the target question is YES, x IS greater than 6
Both cases yield the SAME answer to the
target question
Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: x > 18 - 2y
Rewrite as 18 - 2y < x
Subtract x from both sides to get: 18 - x < 2y
Add 2y to both sides to get: 18 - x < 2y
IMPORTANT: It is given that
y < x
If we multiply both sides by 2 we get another true statement:
2y < 2x
Now add this information to our statement 2 inequality to get: 18 - x < 2y
< 2x
This means that 18 - x
< 2x
Add x to both sides to get: 18 < 3x
Divides both sides by 3 to get:
6 < x
Perfect.
The answer to the target question is YES, x IS greater than 6
Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent