barksdale wrote:David and Mitch. Can you guys please use the math input method? It makes it a lot easier for me to follow along with your math steps. I and I'm sure others in the forum would greatly appreciate it. Thanks!!!
I'm not quite sure what you mean by the
math input method.
Here's an approach similar to David's:
Let x=6.
Plugging x=6 into the numerator of x/(x+y) = 6, we get:
6/(x+y) = 6.
The equation above is valid only if x+y = 1.
Plugging x=6 into x+y = 1, we get:
6+y = 1
y = 1-6 = -5.
Question:
then y/(y+x)?
Plugging x=6 and y=-5 into y/(y+x), we get:
y/(y+x) = -5/(-5+6) = -5/1 = -5.
The correct answer is
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