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If x + x^2 + x^3 = 27, then the average (arithmetic mean)

Expert replies
by M7MBA » Fri Apr 05, 2019 11:21 am

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00:00

Answers

A

B

C

D

E

Stats

Difficulty

If x + x^2 + x^3 = 27, then the average (arithmetic mean) of x + x^2 + x^3 + x^4 is equal to which of the following?

A. 3
B. 3x
C. 7x
D. 9
E. 9x

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
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Source: — Problem Solving |

by GMATinsight » Sat Apr 06, 2019 12:55 am
M7MBA wrote:If x + x^2 + x^3 = 27, then the average (arithmetic mean) of x + x^2 + x^3 + x^4 is equal to which of the following?

A. 3
B. 3x
C. 7x
D. 9
E. 9x

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
Average = (x + x^2 + x^3 + x^4)/4 = x (1 + x+ x^2 + x^3 )/4 = x(1+27)/4 = 28x/4 = 7x

Answer: Option C
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by GMATGuruNY » Sat Apr 06, 2019 2:25 am
GMATinsight wrote:
M7MBA wrote:If x + x^2 + x^3 = 27, then the average (arithmetic mean) of x + x^2 + x^3 + x^4 is equal to which of the following?

A. 3
B. 3x
C. 7x
D. 9
E. 9x
We can PLUG IN THE ANSWERS, which represent the average of x + x² + x³ + x�.

Test B:
(x + x² + x³ + x�)/4 = 3x
Multiplying both sides by 4, we get:
x + x² + x³ + x� = 12x
Dividing both sides by x, we get:
1 + x + x² + x³ = 12
Substituting x+x²+x³=27 into 1+x+x²+x³ = 12, we get:
1 + 27 = 12
28 = 12

The right side needs to be greater.
Test C:
(x + x² + x³ + x�)/4 = 7x
Multiplying both sides by 4, we get:
x + x² + x³ + x� = 28x
Dividing both sides by x, we get:
1 + x + x² + x³ = 28
Substituting x+x²+x³=27 into 1+x+x²+x³ = 28, we get:
1 + 27 = 28
28 = 28
Success!

The correct answer is C.
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