If x is a positive even integer, and n and m are cosecutive integers, then $$\frac{\left(n-m\right)^x}{\left(m-n\right)^x}=?$$ A. -2 B. -1 C. 0 D. 1 E. 2 The OA is D. Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

swerve wrote:If x is a positive even integer, and n and m are cosecutive integers, then $$\frac{\left(n-m\right)^x}{\left(m-n\right)^x}=?$$ A. -2 B. -1 C. 0 D. 1 E. 2 The OA is D. Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks. Pick easy numbers. Say x = 2, n = 4 and m = 3. We want (4-3)^2 /(3-4)^2 = 1^2 / (-1)^2 = 1/1 = 1. The answer is D

swerve wrote:If x is a positive even integer, and n and m are cosecutive integers, then $$\frac{\left(n-m\right)^x}{\left(m-n\right)^x}=?$$ A. -2 B. -1 C. 0 D. 1 E. 2 The OA is D. Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks. You can also use some simple number properties. Because we're raising both expressions to an even exponent, we know both numerator and denominator must be non-negative. We also know that the difference of two consecutive numbers will always be 1 or -1. If they can't be negative, we know both values must equal 1.

The difference between consecutive integers is 1 or -1. Raising to an even power will always produce 1 (because -1 x -1 = 1). And 1/1 = 1 So answer = 1.

Hi swerve, We're told that X is a positive EVEN integer, and N and M are CONSECUTIVE integers. We're asked to find the value of [(N - M)^X] / ([M - N)^X]. This question can be solved by TESTing VALUES. IF... X = 2, N = 2 and M=3.... (2-3)^2 = (-1)^2 = +1 (3-2)^2 = (1)^2 = +1 +1/+1 = +1 Final Answer: D GMAT assassins aren't born, they're made, Rich

swerve wrote:If x is a positive even integer, and n and m are cosecutive integers, then $$\frac{\left(n-m\right)^x}{\left(m-n\right)^x}=?$$ A. -2 B. -1 C. 0 D. 1 E. 2 Notice that (n - m)^x / (m - n)^x = [(n - m)/(m - n)]^x = (-1)^x Since x is a positive even integer, (-1)^x will always be equal to 1. Alternate solution: Let’s use some strategic numbers for n, m, and x. n = 4, m = 3, and x = 2, thus: [(4 - 3)^2]/(3 - 4)^2 = 1^2/(-1)^2 = 1 Answer: D

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