A plane traveled k miles in its first 96 minutes of flight time. If it completed the remaining 300 miles of the trip in t minutes, what was its average speed, in miles per hour, for the entire trip?
$$A.\ 60\frac{\left(k+300\right)}{96+t}$$
$$B.\ kt+96\frac{\left(300\right)}{96t}$$
$$C.\ \frac{k+300}{60\left(96+t\right)}$$
$$D.\ \frac{5k}{8}+\frac{60\left(300\right)}{t}$$
$$E.\ \frac{5k}{8}+5t$$
The OA is A.
The total distance will be,
$$T_{dist}=k+300\ miles$$
And the total time will be,
$$T_{time}=\frac{96+t\ }{60}hours$$
Then the total average speed will be,
$$T_{avg\ speed}=\frac{T_{dist}}{T_{time}}=\frac{k+300}{\frac{96+t}{60}}=60\frac{\left(k+300\right)}{96+t}miles\ per\ hour$$
Now, my question is, is there another way to solve this PS question? Experts, can you help me, please? Thanks!
$$A.\ 60\frac{\left(k+300\right)}{96+t}$$
$$B.\ kt+96\frac{\left(300\right)}{96t}$$
$$C.\ \frac{k+300}{60\left(96+t\right)}$$
$$D.\ \frac{5k}{8}+\frac{60\left(300\right)}{t}$$
$$E.\ \frac{5k}{8}+5t$$
The OA is A.
The total distance will be,
$$T_{dist}=k+300\ miles$$
And the total time will be,
$$T_{time}=\frac{96+t\ }{60}hours$$
Then the total average speed will be,
$$T_{avg\ speed}=\frac{T_{dist}}{T_{time}}=\frac{k+300}{\frac{96+t}{60}}=60\frac{\left(k+300\right)}{96+t}miles\ per\ hour$$
Now, my question is, is there another way to solve this PS question? Experts, can you help me, please? Thanks!
