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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote A plane traveled k miles in its first 96 minutes of flight.. tagged by: AAPL This topic has 2 expert replies and 0 member replies Top Member A plane traveled k miles in its first 96 minutes of flight.. A plane traveled k miles in its first 96 minutes of flight time. If it completed the remaining 300 miles of the trip in t minutes, what was its average speed, in miles per hour, for the entire trip? $$A.\ 60\frac{\left(k+300\right)}{96+t}$$ $$B.\ kt+96\frac{\left(300\right)}{96t}$$ $$C.\ \frac{k+300}{60\left(96+t\right)}$$ $$D.\ \frac{5k}{8}+\frac{60\left(300\right)}{t}$$ $$E.\ \frac{5k}{8}+5t$$ The OA is A. The total distance will be, $$T_{dist}=k+300\ miles$$ And the total time will be, $$T_{time}=\frac{96+t\ }{60}hours$$ Then the total average speed will be, $$T_{avg\ speed}=\frac{T_{dist}}{T_{time}}=\frac{k+300}{\frac{96+t}{60}}=60\frac{\left(k+300\right)}{96+t}miles\ per\ hour$$ Now, my question is, is there another way to solve this PS question? Experts, can you help me, please? Thanks! GMAT/MBA Expert GMAT Instructor Joined 04 Oct 2017 Posted: 551 messages Followed by: 11 members Upvotes: 180 AAPL wrote: A plane traveled k miles in its first 96 minutes of flight time. If it completed the remaining 300 miles of the trip in t minutes, what was its average speed, in miles per hour, for the entire trip? $$A.\ 60\frac{\left(k+300\right)}{96+t}$$ $$B.\ kt+96\frac{\left(300\right)}{96t}$$ $$C.\ \frac{k+300}{60\left(96+t\right)}$$ $$D.\ \frac{5k}{8}+\frac{60\left(300\right)}{t}$$ $$E.\ \frac{5k}{8}+5t$$ The OA is A. The total distance will be, $$T_{dist}=k+300\ miles$$ And the total time will be, $$T_{time}=\frac{96+t\ }{60}hours$$ Then the total average speed will be, $$T_{avg\ speed}=\frac{T_{dist}}{T_{time}}=\frac{k+300}{\frac{96+t}{60}}=60\frac{\left(k+300\right)}{96+t}miles\ per\ hour$$ Now, my question is, is there another way to solve this PS question? Experts, can you help me, please? Thanks! Hello AAPL. The way you solve it is perfect. Another way you could solve it is making the conversion from minutes to hours from the beginning. That is to say, $$96\ \text{minutes}\ =\ \frac{96}{60}\text{hours}$$ and $$t\ \text{minutes}\ =\ \frac{t}{60}\text{hours}.$$ Hence, $$T_{dist}=k+300\ \ \ \ \ and\ \ \ \ \ \ \ \ T_{time}\ =\ \frac{96}{60}+\frac{t}{60}=\frac{96+t}{60}.$$ Therefore, $$T_{avg\ speed}=\frac{T_{dist}}{T_{time}}\ =\ \frac{300+k}{\frac{96+t}{60}}=60\ \frac{\left(300+k\right)}{96+t}$$ So, the correct answer is the option A. I hope this answer also can help you. I'm available if you'd like a follow-up. Regards. _________________ GMAT Prep From The Economist We offer 70+ point score improvement money back guarantee. Our average student improves 98 points. Free 7-Day Test Prep with Economist GMAT Tutor - Receive free access to the top-rated GMAT prep course including a 1-on-1 strategy session, 2 full-length tests, and 5 ask-a-tutor messages. Get started now. GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2950 messages Followed by: 19 members Upvotes: 43 AAPL wrote: A plane traveled k miles in its first 96 minutes of flight time. If it completed the remaining 300 miles of the trip in t minutes, what was its average speed, in miles per hour, for the entire trip? $$A.\ 60\frac{\left(k+300\right)}{96+t}$$ $$B.\ kt+96\frac{\left(300\right)}{96t}$$ $$C.\ \frac{k+300}{60\left(96+t\right)}$$ $$D.\ \frac{5k}{8}+\frac{60\left(300\right)}{t}$$ $$E.\ \frac{5k}{8}+5t$$ We are given that a plane traveled k miles in 96 minutes. Since we need the average speed in miles per hour we can convert 96 minutes to hours. 96 minutes = 96/60 = 8/5 hours We are also given that the plane completed the remaining 300 miles in t minutes. We must also convert t minutes to hours. t minutes = t/60 hours Now we can calculate the average speed for the entire trip, using the formula for average speed. Average speed = total distance/total time Average speed = (k + 300)/(8/5 + t/60) Average speed = (k + 300)/(96/60+t/60) Average speed = (k + 300)/((96 + t)/60) Average speed = 60(k + 300)/(96 + t) Answer: A _________________ Scott Woodbury-Stewart Founder and CEO scott@targettestprep.com See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

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