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If x and y are positive integers and 1 + x + y + xy = 15 ...

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by mitzwillrockgmat » Thu May 20, 2010 2:24 am
If x and y are positive integers and 1 + x + y + xy = 15, what is the value of x + y?

A. 3
B. 5
C. 6
D. 8
E. 9

Please help explain this futher! I get to this point: (1 + x) (1 + y) =15 but what do i do further to get the answer 6?

1 + x + y + xy = 15
1 + x + y(1 + x) =15
(1+x)(1+ y)=15

now what?? thank you! :)
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Source: — Problem Solving |

by liferocks » Thu May 20, 2010 2:32 am
1 + x + y + xy = 15
or (1+x)(1+y)=15
15 can be expressed as multiple of two integers as (1,15)and (3,5)

if (1+x)(1+y)=1*15..1+x=1 or x=0 and y=14..so x+y=14
if (1+x)(1+y)=3*5..1+x=3 or x=2 and y=4..so x+y=6

only C is in ans choice
ans option C
Last edited by liferocks on Thu May 20, 2010 2:42 am, edited 1 time in total.
"If you don't know where you are going, any road will get you there."
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by sanju09 » Thu May 20, 2010 2:37 am
liferocks wrote:1 + x + y + xy = 15
or (1+x)(1+y)=15
15 can be expressed as multiple (or the product?) of two integers as (1,15)and (3,5)

if (1+x)(1+y)=1*15..1+x=1 or x=0 and y=14..so x+y=14.............not applicable
if (1+x)(1+y)=3*5..1+x=3 or x=2 and y=4..so x+y=6....now edited

only C is in ans choice
ans option C
[spoiler]You need to get rid of this...good to see that you have edited while I was quoting your work, and why did you use the spoiler function above?[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by liferocks » Thu May 20, 2010 2:42 am
sanju09 wrote:
liferocks wrote:1 + x + y + xy = 15
or (1+x)(1+y)=15
15 can be expressed as multiple (or the product?) of two integers as (1,15)and (3,5)

if (1+x)(1+y)=1*15..1+x=1 or x=0 and y=14..so x+y=14.............not applicable
if (1+x)(1+y)=3*5..1+x=3 or x=2 and y=4..so x+y=6....now edited

only C is in ans choice
ans option C
[spoiler]You need to get rid of this...good to see that you have edited while I was quoting your work, and why did you use the spoiler function above?[/spoiler]
Now used the spoiler in both places
"If you don't know where you are going, any road will get you there."
Lewis Carroll
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by sanju09 » Thu May 20, 2010 2:48 am
...and what should be the correct wordings in this case?

this: 15 can be expressed as multiple of two integers

or that: 15 can be expressed as the product of two integers

multiple and the product are two different words with different meanings in mathematics
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by liferocks » Thu May 20, 2010 2:51 am
sanju09 wrote:...and what should be the correct wordings in this case?

this: 15 can be expressed as multiple of two integers

or that: 15 can be expressed as the product of two integers
Hmm..second one is definitely right and conveys the meaning correctly..but technically first one is also correct if we take a multiplicity factor as 1 :D
"If you don't know where you are going, any road will get you there."
Lewis Carroll
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by sanju09 » Thu May 20, 2010 2:54 am
liferocks wrote:
sanju09 wrote:...and what should be the correct wordings in this case?

this: 15 can be expressed as multiple of two integers

or that: 15 can be expressed as the product of two integers
Hmm..second one is definitely right and conveys the meaning correctly..but technically first one is also correct if we take a multiplicity factor as 1 :D
postmortem is not carried out on living beings
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by kstv » Thu May 20, 2010 3:04 am
if (1+x)(1+y) = 15
and x any y are +ve integers
then (1+x) (1+y) = 5*3 and not 15*1
cos 1+x or 1+y = 1 implies x or y = 0
if 1+x = 5
1+y = 3
it is not necessary to find the values of x and y seperately
adding the two (1+x)+(1+y) = 8
x+y = 6
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by sanju09 » Thu May 20, 2010 3:10 am
kstv wrote:if (1+x)(1+y) = 15
and x any y are +ve integers
then (1+x) (1+y) = 5*3 and not 15*1
cos 1+x or 1+y = 1 implies x or y = 0
if 1+x = 5
1+y = 3
it is not necessary to find the values of x and y seperately
adding the two (1+x)+(1+y) = 8
x+y = 6
your name was missing in the hit list of my Quant Commandos
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion