LUANDATO wrote:If x and y are nonzero integers, is x/y > 0?
(1) |x^3|= |y^3|
(2) |x + y| = |x| + |y|
The OA is B.
I need help with this DS question. Please, can any expert explain it for me? Thanks.
For x/y > 0, x and y must be of the same sign. Either both positive or both negative.
(1) |x^3| = |y^3|
Case 1: x = y = 2, then the answer is Yes.
Case 2: x = 2 and y = -2, then the answer is No.
(2) |x + y| = |x| + |y|
Case 1: At x = y = 2, |x + y| = |x| + |y| = |2 + 2| = |2| + |2| => 4 = 4. The answer is Yes.
Case 2: x = 2 and y = -2, |x + y| = |x| + |y| = |2 - 2| = |2| + |-2| => 0 ≠4. This is not a valid case.
Case 3: At x = y = -2, |x + y| = |x| + |y| = |-2 - 2| = |-2| + |-2| => 4 = 4. The answer is Yes.
Thus, only Case 1 and Case 3 are applicable. The answer is Yes, x/y > 0. Sufficient.
The correct answer:
B
Hope this helps!
-Jay
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