LUANDATO wrote:If x ≠0 and
$$\frac{\left(x+1\right)^2}{-1}-x\ =\ \frac{y}{x}$$
Then y = ?
A. 2x
B. 2x-1
C. 2x+1
D. 2x^2-1
E. 2x^2+1
Let x=-1.
Plugging x=-1 into the given equation, we get:
$$\frac{\left(-1+1\right)^2}{-1}-(-1)\ =\ \frac{y}{-1}$$
0 + 1 = -y
1 = -y
y = -1.
Since the question stem asks for the value of y, the target value is -1.
Now plug x=-1 into the answers to see which yields the target value of -1.
Only
C works:
2x+1 = (2)(-1) + 1 = -2+1 = -1.
The correct answer is
C.
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