ch0719 wrote:if x^2-x-6<0, what is the value of x?

1. x is an positive integer
2. -2<x<2

I found this somewhere on the web, the answer given is A but I thought it should be E, what do you think?

x^2-x-6<0 only when -2 < X < 3

So Statement 1 can not be sufficient. TRY 100 and you wont get a negative number

Statement 2 is a subset of -2 < X < 3 and sufficient.

So I would go with B

Let me add to the confusion more

How abt C)???

x^2-x-6<0
x^2-x<6
x(x-1)<6

or

(x+2) (x-3) < 0

Stmt I

x could be 1,2. No need to analayze any further analysis multiple values x INSUFF

Stmt II

-2<x<2

x could have multiple value satisfying (x+2) (x-3) < 0

-1,0,1.... (just considering integers(not anydecimal values) wihtin this range)

Highly INSUFF

Stmt I and II together

x has to be 1

SUFF

Choose C)

So Cramya you really think that -1,0 wont satisfy the equation?

For 0 it is -6 <0

For -1 it is -4 < 0

So I guess PUFF PUFF PASS

Oh by the way, what is HIGHLY INSUFF ?

Oh by the way, what is HIGHLY INSUFF

->

One that opens up a world of POSSIBILTIES.

Since x did not have to be an integer based on stm II imagine if we had considered all the decimal values between the given range that satisfied the conditions...

Cramya,

Did you study Math in the college ? If not, here is the Calculus 101

In fact, if you learn how to construct this tables you will really like them!

what is the value of x ?

Okay - End of misunderstanding.

Cramya, I thought that you are saying that -1 and 0 will not satisfy the equation. My bad.

And yes the answer is C because we are looking for a VALUE not a RANGE so

any numbers within the range given in B will satisfy the equation but the only POSITIVE integer is + 1, since +2 is not included.

thanks

given the statement 1 and 2, we can already conclude that the only possible outcome of x is 1, because x has to be a positive int and it has to be lower than a 2, then it got to be 1 regardless of what the question is asking

therefore i guess the question may be not too legit

therefore i guess the question may be not too legit

What website is the source?

cramya wrote:





Cramya
(x+2) (x-3

cramya,
vaulue of X here would be x<-2 and x<3 isnt it but acc to u ..it is
between -2 <x<3 , how cm

if u put x+2<0
u ll get x<-2
or x>-2
Pls explain

cramya,
vaulue of X here would be x<-2 and x<3 isnt it but acc to u ..it is
between -2 <x<3 , how cm

if u put x+2<0
u ll get x<-2
or x>-2

I dont think I said -2 <x<3 in my post. I am missing something. Let em know.

(x+2) (x-3) < 0 is from the whats given

I was telling -2<x<2 (stmt 2) is insuffcient since -1,0,1 all fit the bill

sorry, it was said by Logitech but if logitech has done this, this is not correct...am i rite.
it is basic but i am not confident of my inequality skills
so,
x+2 <0
means x< -2..
am i rite...this is my ques.

Hello Vivek,

It is -2<x<3 because, because when you factorize,

(x-3)(x+2)<0

so, only one of the two factors can be negative, and the other one has to positive.

hence, x-3 will be negative only when x<3, and x+2 will be negative, only when x>-2...

hence, we get

-2 < x< 3


even i think that the answer will be C,

since only A and B just narrow down this range, however both combined limit the answer to just 1.

x^2 -x-6<0

(x+2)(x-3)<0

-2<x<3

a, not enough

b, not enouth

c, 0<x<2 and x positive interger

x must be 1