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If the area of a square with sides of length 8 centimeters..

Expert replies
by BTGmoderatorLU » Thu Mar 01, 2018 10:52 am
If the area of a square with sides length 8 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?

A. 4
B. 8
C. 12
D. 16
E. 18

The OA is D.

If the square has a side of 8 centimeters and its area is equal to the area of a rectangle width a width of 4 centimeters, then
$$A_{square}=A_{rectangle}$$
$$8^2=4\cdot L\ \Rightarrow \ L=\frac{64}{4}=16\ centimeters$$
Experts, any suggestion about this PS question? Thanks in advance.
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Source: — Problem Solving |

by mbawisdom » Mon Mar 05, 2018 8:10 am
LUANDATO wrote:If the area of a square with sides length 8 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?

A. 4
B. 8
C. 12
D. 16
E. 18

The OA is D.

If the square has a side of 8 centimeters and its area is equal to the area of a rectangle width a width of 4 centimeters, then
$$A_{square}=A_{rectangle}$$
$$8^2=4\cdot L\ \Rightarrow \ L=\frac{64}{4}=16\ centimeters$$
Experts, any suggestion about this PS question? Thanks in advance.
Your approach looks good to me. I would have set it up in the same way.
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by Jeff@TargetTestPrep » Tue Mar 06, 2018 10:34 am
LUANDATO wrote:If the area of a square with sides length 8 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?

A. 4
B. 8
C. 12
D. 16
E. 18
We can create the equation:

8^2 = 4L

64 = 4L

16 = L

Answer: D

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