If T divided by B equals 8.12 what is a possible remainder?

Hello AAPL.

I would solve it as follows:

We know that T divided by B equals 8.12, then $$\frac{T}{B}=8.12\ \ \ \Rightarrow\ T=8.12\ B\ \ \Rightarrow\ \ T=\left(8+0.12\right)B\ \ \Rightarrow\ \ T=8B\ +\ \frac{12}{100}B$$ $$\Rightarrow\ \ \ T=8B\ +\ \frac{3}{25}B$$ $$\Rightarrow\ \ \ 25T=200B\ +\ 3B$$ Here we see that the remainder (3B) is a multiple of 3.

The unique multiple of 3 is [spoiler]C=9[/spoiler].

If t is divided by b,
ie t/b = 8.12
ie 8.12

8[12][/100] = 8[3][/5] ie 8 + 3/5
so, it means thats t/b = 3/25
ie t = 3b+25 where t is teh reaminder.

So, it means the remainder is the multiple of 3.
In these options, only 9 is a multiple of 3.
So the answer is C.

Regards!

AAPL wrote:If T divided by B equals 8.12 what is a possible remainder?

A. 2
B. 8
C. 9
D. 26
E. 44

We can create the remainder equation of:

T/B = 8 + 12/100

T/B = 8 + 3/25

Thus, we see that the remainder must be a multiple of 3, so 9 is a possible remainder.

Answer: C