If points A and B are randomly placed on the circumference of a circle with radius 2, what is the probability that the l

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If points A and B are randomly placed on the circumference of a circle with radius 2, what is the probability that the length of chord AB is greater than 2?

A) 1/4
B) 1/3
C) 1/2
D) 2/3
E) 3/4

Answer: D
Source: Magoosh
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BTGModeratorVI wrote:
Fri Apr 10, 2020 8:14 am
If points A and B are randomly placed on the circumference of a circle with radius 2, what is the probability that the length of chord AB is greater than 2?

A) 1/4
B) 1/3
C) 1/2
D) 2/3
E) 3/4

Answer: D
Source: Magoosh
We'll begin by arbitrarily placing point A somewhere on the circumference.
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So, we want to know the probability that a randomly-placed point B will yield a chord AB that is at least 2 cm long.
So, let's first find a location for point B that creates a chord that is EXACTLY 2 cm long.
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There's also ANOTHER location for point B that creates another chord that is EXACTLY 2 cm long.
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IMPORTANT: For chord AB to be greater than or equal to 2 cm, point B must be placed somewhere along the red portion of the circle's circumference.
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So, the question really boils down to, "What is the probability that point B is randomly placed somewhere on the red line?"
To determine this probability, notice that the 2 cm chords are the same length as the circle's radius (2 cm)
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Since these 2 triangles have sides of equal length, they are equilateral triangles, which means each interior angle is 60 degrees.
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The 2 central angles (from the equilateral triangles) add to 120 degrees.
This means the remaining central angle must be 240 degrees.
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This tells us that the red portion of the circle represents 240/360 of the entire circle.
So, P(point B is randomly placed somewhere on the red line) = 240/360 = 2/3

Answer: D
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BTGModeratorVI wrote:
Fri Apr 10, 2020 8:14 am
If points A and B are randomly placed on the circumference of a circle with radius 2, what is the probability that the length of chord AB is greater than 2?

A) 1/4
B) 1/3
C) 1/2
D) 2/3
E) 3/4

Answer: D
Source: Magoosh
Let O be the center of the circle. If we fix point A somewhere on the circumference of the circle, and if B is anywhere on the right or left of point A such that angle AOB is no greater than 60 degrees, then the length of chord AB will be no greater than 2. That is, since B can be to the right or left of point A, then B can be anywhere on a 60 + 60 = 120-degree arc (where A is the center of this arc) such that chord AB is no longer than 2. However, if B is anywhere outside this 120-degree arc (i.e., B is anywhere on the 240-degree arc that is outside of the 120-degree arc), then chord AB will be longer than 2. Since the circle has 360 degrees, the probability B is on the 240-degree arc is 240/360 = 2/3.

Answer: D

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