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If p is a positive integer, is p^2 divisible by 96?

Expert replies
by BTGmoderatorDC » Sun Jan 31, 2021 4:39 pm

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C

D

E

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If p is a positive integer, is p^2 divisible by 96?

(1) p is a multiple of 8.
(2) p^2 is a multiple of 12.


OA C

Source: Manhattan Prep
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Source: — Data Sufficiency |

BTGmoderatorDC wrote:
Sun Jan 31, 2021 4:39 pm
If p is a positive integer, is p^2 divisible by 96?

(1) p is a multiple of 8.
(2) p^2 is a multiple of 12.


OA C

Source: Manhattan Prep
Target question: Is p² divisible by 96?
This is a good candidate for rephrasing the target question.

-----ASIDE---------------------
A lot of integer property questions can be solved using prime factorization.
For questions involving divisibility, divisors, factors and multiples, we can say:
If N is divisible by k, then k is "hiding" within the prime factorization of N

Consider these examples:
24 is divisible by 3 because 24 = (2)(2)(2)(3)
Likewise, 70 is divisible by 5 because 70 = (2)(5)(7)
And 112 is divisible by 8 because 112 = (2)(2)(2)(2)(7)
And 630 is divisible by 15 because 630 = (2)(3)(3)(5)(7)
--------------------------

Since 96 = (2)(2)(2)(2)(3), we can rephrase the target question as:
REPHRASED target question: Are there four 2's and one 3 hiding in the prime factorization of p² ?

Aside: the video below has tips on rephrasing the target question

Statement 1: p is a multiple of 8
In other words, p is divisible by 8
8 = (2)(2)(2)
So, we know that there are at least three 2's hiding in the prime factorization of p
This also tells us that there are SIX 2's hiding in the prime factorization of p²
Unfortunately this information is not sufficient to answer the target question.
Consider these two possible cases:
Case a: p = 8, in which case p² = 64. In this case, the answer to the target question is NO, p² is NOT divisible by 96
Case b: p = 24, in which case p² = 576. In this case, the answer to the target question is YES, p² IS divisible by 96
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: p² is a multiple of 12
12 = (2)(2)(3)
So, we know that there are at least two 2's and one 3 hiding in the prime factorization of p²
Unfortunately this information is not sufficient to answer the target question.
Consider these two possible cases:
Case a: p = 12, in which case p² = 144 (which is divisible by 12). In this case, the answer to the target question is NO, p² is NOT divisible by 96
Case b: p = 24, in which case p² = 576 (which is divisible by 12). In this case, the answer to the target question is YES, p² IS divisible by 96
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that there are SIX 2's hiding in the prime factorization of p²
Statement 2 tells us that there is at least ONE 3 hiding in the prime factorization of p²
So, when we combine the two statements, we can be certain that there are at least four 2's and one 3 hiding in the prime factorization of p²
Since we can answer the REPHRASED target question with certainty, the combined statements are SUFFICIENT

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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