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Given that n & p are not both odd, and non-negative integers, we have one of n and p even and the other is odd. With this information in mind, let's see the options.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
If n=p=0, options A, B, C and D each yield a even value, indicating that these options do NOT have to be odd.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
So we see that n and p could be odd/even, even/odd, or both even.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
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